The physical quantity having dimensions $2$ in length is:

Power

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Acceleration

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Force constant

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Stress

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Solution

The correct option is B Power
$P o w e r = M L^{2} T^{- 3}$
$A c c e l e r a t i o n = L T^{- 2}$
$f o r c e c o n s t a n t = M^{1} L^{0} T^{- 2}$
$S t r e s s = F / A = M L^{- 1} T^{- 2}$
Hence, option A is correct.

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Similar questions

Q. The physical quantity having the dimensions

[M^{- 1} L^{- 3} T^{3} A^{2}]

Q. The physical quantity having the dimensions

[M^{- 1} T^{3} L^{- 3} A^{2}]

is:

Can you add two vectors representing physical quantities having different dimensions? Can you multiply two vectors representing physical quantities having different dimensions?

Q. The physical quantities not having same dimensions are :

If two quantities have same dimensions, they represent same physical quantity.

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The physical quantity having dimensions 2 in length is:

The correct option is B PowerPower=ML2T−3Acceleration=LT−2force constant=M1L0T−2Stress=F/A=ML−1T−2Hence, option A is correct.

The physical quantity having dimensions $2$ in length is:

The correct option is B Power
$P o w e r = M L^{2} T^{- 3}$
$A c c e l e r a t i o n = L T^{- 2}$
$f o r c e c o n s t a n t = M^{1} L^{0} T^{- 2}$
$S t r e s s = F / A = M L^{- 1} T^{- 2}$
Hence, option A is correct.