The physical quantity having the dimensions $[M^{- 1} T^{3} L^{- 3} A^{2}]$ is:

resistance

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resistivity

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electrical conductivity

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electromotive force

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Solution

The correct option is C electrical conductivity
Electrical conductivity is given as,
$σ = \frac{G l}{a}$
where $G$ is the conductance i.e. $G = \frac{I}{V}$
So, $[σ] = [\frac{G l}{a}] = [\frac{I l}{V a}] = [\frac{A L}{M L^{2} T^{- 2} L^{2} / A T}]$
$⟹ [σ] = [M^{- 1} T^{3} L^{- 3} A^{2}]$

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The physical quantity having the dimensions [M−1T3L−3A2] is:

The correct option is C electrical conductivityElectrical conductivity is given as,σ=Glawhere G is the conductance i.e. G=IVSo, [σ]=[Gla]=[IlVa]=[ALML2T−2L2/AT]⟹[σ]=[M−1T3L−3A2]

The physical quantity having the dimensions $[M^{- 1} T^{3} L^{- 3} A^{2}]$ is:

The correct option is C electrical conductivity
Electrical conductivity is given as,
$σ = \frac{G l}{a}$
where $G$ is the conductance i.e. $G = \frac{I}{V}$
So, $[σ] = [\frac{G l}{a}] = [\frac{I l}{V a}] = [\frac{A L}{M L^{2} T^{- 2} L^{2} / A T}]$
$⟹ [σ] = [M^{- 1} T^{3} L^{- 3} A^{2}]$