Question

The pie-chart given in Fig. 25.18 shows the annual agricultural production of an Indian state. If the total production of all the commodities is 81000 tonnes, find the production (in tonnes) of
(i) Wheat
(ii) Sugar
(iii) Rice
(iv) Maize
(v) Gram

Answer 1

(i)
$$\begin{gathered} \mathrm{Production}\mathrm{of}\mathrm{wheat}=\frac{\mathrm{Central}\mathrm{angle}\mathrm{for}\mathrm{wheat}\times \mathrm{Total}\mathrm{production}}{360°} \\ =\frac{120°\times 81000}{360°}=27000\mathrm{tonnes} \end{gathered}$$

(ii)
$$\begin{gathered} \mathrm{Production}\mathrm{of}\mathrm{sugar}=\frac{\mathrm{Central}\mathrm{angle}\mathrm{for}\mathrm{sugar}\times \mathrm{Total}\mathrm{production}}{360°} \\ =\frac{10°\times 81000}{360°}=22500\mathrm{tonnes} \end{gathered}$$

(iii)
$$\begin{gathered} \mathrm{Production}\mathrm{of}\mathrm{rice}=\frac{\mathrm{Central}\mathrm{angle}\mathrm{for}\mathrm{Rice}\times \mathrm{Total}\mathrm{production}}{360°} \\ =\frac{60°\times 81000}{360°}=13500\mathrm{tonnes} \end{gathered}$$

(iv)
$$\begin{gathered} \mathrm{Production}\mathrm{of}\mathrm{maize}=\frac{\mathrm{Central}\mathrm{angle}\mathrm{for}\mathrm{maize}\times \mathrm{Total}\mathrm{production}}{360°} \\ =\frac{30°\times 81000}{360°}=6750\mathrm{tonnes} \end{gathered}$$

(v)
$$\begin{gathered} \mathrm{Production}\mathrm{of}\mathrm{gram}=\frac{\mathrm{Central}\mathrm{angle}\mathrm{for}\mathrm{Gram}\times \mathrm{Total}\mathrm{production}}{360°} \\ =\frac{120°\times 81000}{360°}=11250\mathrm{tonnes} \end{gathered}$$