Question

The pipe shows the volume flow rate of an ideal liquid at certain time and its direction. What is the value of $Q$ in $m^3$ /s? (Assume steady state and equal area of cross section at each opening)

• A. $10\times {10}^{-6}$
• B. $11\times {10}^{-6}$
• C. $13\times {10}^{-6}$
• D. $18\times {10}^{-6}$

Answer 1

The correct option is C $13\times {10}^{-6}$

Since there is no leakage of water, So
total amount of water entering the pipe per second= total amount of water leaving the pipe per second
$\Rightarrow (4\times {10}^{-6})+(4\times {10}^{-6})+Q=(8\times {10}^{-6})+(2\times {10}^{-6})+(5\times {10}^{-6})+(6\times {10}^{-6})$
$\Rightarrow Q=13\times {10}^{-6}{m}^3/s$