Question

The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of $1.0m$. If the piston moves with simple harmonic motion with an angular frequency of $200rad/min$ , what is its maximum speed?

Answer 1

Given,

Angular frequency of the piston,$\omega =200rad/min$

Stroke $=1.0m$

Amplitude,$A=\frac{1.0}{5}=0.5m$

The maximum speed $v_{max}$ of the piston is given by

the relation:

$v_{max}=A\omega$

$=200\times 0.5$

$=100m/min$

Therefore, its maximum speed is $100m/min$.