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Capillary Action

The piston is...

Question

The piston is taken completely out of the cylinder. The hole at the top is sealed. A water tank is brought below the cylinder and put in a position so that the water surface in the tank is at the same level as the top of the cylinder as shown in figure. The density of water is d. In equilibrium,the height H of the water column in the cylinder satisfies
a. dg(L₀-H)² + P₀(L₀-H) + L₀P₀=0
b.. dg(L₀-H)²- P₀(L₀-H) - L₀P₀=0
c. dg(L₀-H)² + P₀(L₀-H) -L₀P₀=0
d.. dg(L₀-H)² - P₀(L₀-H) + L₀P₀=0

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Solution

Considering Boyle's Law PV= Const
And equating it to bottom of the Beaker We get The first Eqn.

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