The pitch of a screw gauge is 0.5 mm and there are 100 divisions on its circular scale. The instrument reads +2 circular scale divisions when nothing is put in-between its jaws. In measuring the diameter of a wire, there are 8 divisions on the main scale and $83^{r d}$ circular scale division coincides with the reference line. Then the diameter of the wire is:

4.05 mm

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4.405 mm

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3.05 mm

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1.25 mm

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Solution

The correct option is B 4.405 mm
R=8(M.S.D)+83(L.C)-zero error
=8(0.5)+21(0.005)

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The correct option is B 4.405 mmR=8(M.S.D)+83(L.C)-zero error =8(0.5)+21(0.005)

The correct option is B 4.405 mm
R=8(M.S.D)+83(L.C)-zero error
=8(0.5)+21(0.005)