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Question

The pitch of a screw gauge is 2 mm and there are 100 divisions on the circular scale. In measuring the diameter of a sphere, there are 6 divisions on the linear scale and 40 divisions on circular scale coinciding with the reference line. The diameter of the sphere is:

A
6.4 mm
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B
12.8 mm
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C
3.2 mm
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D
20 mm
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Solution

The correct option is B 12.8 mm
Least count (LC) of screw gauge
= pitchno. of division on circular scale=2100=0.02 mm

From the data given in the question,
Circular scale reading
=(LC)×no. of division on circular scale coinciding=0.02×40=0.8 mm
Linear scale reading =no. of division on linear scale coinciding×pitch=6×2=12 mm
Total reading = Linear scale reading + Circular scale reading
= 12 + 0.8 = 12.8 mm
Diameter =12.8 mm.
Hence, option (b) is the correct answer.

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