You visited us 6 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

More about Magnetic Dipoles

The pitch of ...

Question

The pitch of the helical path of the motion of the particle will be

\frac{π}{100} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{125} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{215} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{250} m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{π}{250} m$
$Given:-$ $(\frac{q}{m})$ = $\frac{1063}{19}$ C/Kg

$\to B = (20^i + 30^j + 50^k)$ T

$\to v = (20^i + 50^j + 30^k)$ m/s

$To find:-$ pitch of the helical path

$Solution:-$

Pitch= TV cos $θ$

= $\frac{1}{f} V \frac{\to V \to B}{B V} = \frac{π \sqrt{38} \times 400}{10^{4} \sqrt{3800}} = \frac{4 π}{10^{3}} m = \frac{π}{250} m$

$Hence the correct option is D$

Suggest Corrections

Similar questions

Q. A charged particle is fired at an angle

θ

to a uniform magnetic field directed along the

x -

axis. During its motion along a helical path, if the pitch of the helical path is equal to the maximum distance of the particle from the

x -

axis, then

A charged particle enters a uniform magnetic field with velocity vector at an angle of 45⁰ with the magnetic field. The pitch of the helical path followed by the particle is p. The radius of the helix will be

Q. A particle of mass

400 g

is executing SHM of amplitude

0.4 m

. When it passes through the mean position, its kinetic energy is

32 \times 10^{- 3} J

. If the initial phase of oscillation is

\frac{π}{4}

, then the equation of motion of the particle is

Q. What will be the displacement equation of the simple harmonic motion obtained by combining the motions?

x_{1} = 2 sin ω t

x_{2} = 4 sin (ω t + \frac{π}{6})

and

x_{3} = 6 sin (ω t + \frac{π}{3})

Q. Two simple harmonic motions are represented by the equations

y_{1} = 0.1 sin (100 π t + \frac{π}{3})

and

y_{2} = 0.1 cos π t

. The phase difference of the velocity of particle

1

with respect to the velocity of particle

2

Join BYJU'S Learning Program

The pitch of the helical path of the motion of the particle will be

The correct option is D π250mGiven:- (qm)= 106319 C/Kg →B=(20^i+30^j+50^k)T →v=(20^i+50^j+30^k)m/sTo find:-pitch of the helical pathSolution:-Pitch= TV cos θ =1fV→V→BBV=π√38×400104√3800=4π103m=π250mHence the correct option is D