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Accuracy and Precision

The pitch of ...

Question

The pitch of the screw gauge is $0.5$ mm. Its circular scale contains $50$ divisions. The least count of the screw gauge is:

A

0.001 mm

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B

0.01 mm

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C

0.02 mm

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D

0.025 mm

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Solution

The correct option is B 0.01 mm
Least count $= \frac{P i t c h}{T o t a l n u m b e r o f d i v i s i o n s o n t h e c i r c u l a r s c a l e} = \frac{0.5}{50} = 0.01 m m$

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