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Question

The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffer solution of HA in which 50% of the acid is ionized is:

A
7.0
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B
4.5
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C
2.5
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D
9.5
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Solution

The correct option is D 9.5
pH=pKa+log[Conjugate base][acid]

pKa=4.5

[Conjugate base]=[acid], as 50% ionification

pH=4.5+log0.50.5

pH=4.5

Then, pOH=144.5=9.5

Note: (pH+pOH=14)

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