The $p K_{a}$ of a weak acid is 4.8. What is the ratio of [salt] to [acid], if a buffer of $p H = 5.8$ is to be prepared?
(2000)

1:1

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10:1

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2:1

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1:10

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Solution

The correct option is B 10:1
The expression for the pH of the acidic buffer solution is as given below.
$p H = p K_{a} + l o g \frac{[S a l t]}{[A c i d]}$
$p K_{a} = 4.8$
Substitute values in the above equation.
$5.8 = 4.8 + l o g \frac{[S a l t]}{[A c i d]}$
Hence, $\frac{[S a l t]}{[A c i d]} = \frac{10}{1} = 10 : 1$ .

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The pKa of a weak acid is 4.8. What is the ratio of [salt] to [acid], if a buffer of pH=5.8 is to be prepared? (2000)

The correct option is B 10:1The expression for the pH of the acidic buffer solution is as given below.pH=pKa+log[Salt][Acid]pKa=4.8Substitute values in the above equation.5.8=4.8+log[Salt][Acid]Hence, [Salt][Acid]=101=10:1.

The $p K_{a}$ of a weak acid is 4.8. What is the ratio of [salt] to [acid], if a buffer of $p H = 5.8$ is to be prepared?
(2000)