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Standard XII

Chemistry

Acidic Buffer Action

The pKa of ...

Question

The $p K_{a}$ of a weak acid is $4.8$ . What should be the ratio of [Acid]/[Salt] of a buffer if $p H = 5.8$ is required?

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Solution

The correct option is D $0.1$
$p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}$

$5.8 = 4.8 + log \frac{[S a l t]}{[A c i d]}$ or $log \frac{[S a l t]}{[A c i d]} = 1.0$

$\frac{[S a l t]}{[A c i d]} =$ anti $log 1.0 = 10$

$\frac{[A c i d]}{[S a l t]} = \frac{1}{10} = 0.1$

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The pKa of a weak acid is 4.8. What should be the ratio of [Acid]/[Salt] of a buffer if pH=5.8 is required?

The correct option is D 0.1pH=pKa+log[Salt][Acid]5.8=4.8+log[Salt][Acid] or log[Salt][Acid]=1.0[Salt][Acid]= anti log1.0=10[Acid][Salt]=110=0.1

The $p K_{a}$ of a weak acid is $4.8$ . What should be the ratio of [Acid]/[Salt] of a buffer if $p H = 5.8$ is required?

The correct option is D $0.1$
$p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}$

$5.8 = 4.8 + log \frac{[S a l t]}{[A c i d]}$ or $log \frac{[S a l t]}{[A c i d]} = 1.0$

$\frac{[S a l t]}{[A c i d]} =$ anti $log 1.0 = 10$

$\frac{[A c i d]}{[S a l t]} = \frac{1}{10} = 0.1$