You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Acidic Buffer Action

The pKa of ...

Question

The $p K_{a}$ of a weak acid is $4.8$ . What should be the ratio of [Acid]/[Salt] of a buffer if $p H = 5.8$ is required?

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $0.1$
$p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}$

$5.8 = 4.8 + log \frac{[S a l t]}{[A c i d]}$ or $log \frac{[S a l t]}{[A c i d]} = 1.0$

$\frac{[S a l t]}{[A c i d]} =$ anti $log 1.0 = 10$

$\frac{[A c i d]}{[S a l t]} = \frac{1}{10} = 0.1$

Suggest Corrections

Similar questions

Q. For a weak acid

p K_{a}

4.8

, what will be the ratio of concentration of acid and salt in pH

5.8

solution?

Q. The

p^{k a}

of a certain weak acid is 4.0 what should be the [salt] to [acid] ratio if we have to prepare a buffer with

p H = 5

using the acid and one of the salts?
(1992)

A physician wishes to prepare a buffer solution at pH = 4.41 that efficiently resist change in pH yet contains only small concentration of the buffering agents. Which one of the following weak acid together with its sodium salt should be best to use?

Q. A buffer solution is made by mixing a weak acid

H A (K_{a} = 10^{- 6})

with its salt NaA in equal amounts. what should be the amount of acid or salt that should be added to make 90 ml of buffer solution of buffer capacity 0.1 ?

Q. The

p H

of a simple sodium acetate buffer is given by

p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}

K_{a}

of acetic acid

= 1.8 \times 10^{- 5}

If [Salt]=[Acid]

= 0.1 M

, the

p H

of the solution would be about:

Join BYJU'S Learning Program

The pKa of a weak acid is 4.8. What should be the ratio of [Acid]/[Salt] of a buffer if pH=5.8 is required?

The correct option is D 0.1pH=pKa+log[Salt][Acid]5.8=4.8+log[Salt][Acid] or log[Salt][Acid]=1.0[Salt][Acid]= anti log1.0=10[Acid][Salt]=110=0.1

The $p K_{a}$ of a weak acid is $4.8$ . What should be the ratio of [Acid]/[Salt] of a buffer if $p H = 5.8$ is required?

The correct option is D $0.1$
$p H = p K_{a} + log \frac{[S a l t]}{[A c i d]}$

$5.8 = 4.8 + log \frac{[S a l t]}{[A c i d]}$ or $log \frac{[S a l t]}{[A c i d]} = 1.0$

$\frac{[S a l t]}{[A c i d]} =$ anti $log 1.0 = 10$

$\frac{[A c i d]}{[S a l t]} = \frac{1}{10} = 0.1$