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Question

The planar compounds is/are:

A
¨N(SiH3)3
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B
IF4
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C
BF3
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D
BrF3
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Solution

The correct options are
A ¨N(SiH3)3
B IF4
C BF3
D BrF3
In (SiH3)3N, Si has vacant d orbitals which provides pπdπ bonding and so, nitrogen has sp2 hybridization with trigonal planar shape.
IF4 is square planar.
BF3 trigonal planar.
BrF3 trigonal planar.

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