The plane containing the two lines x-3-1-y-2-4-z-1-5 and x-2-1-y-3-4-z-1-5 is 11 x-m y-n z-28- where

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Condition for a Line to Lie on a Plane

The plane con...

Question

The plane containing the two lines $\frac{x - 3}{1} = \frac{y - 2}{4} = \frac{z - 1}{5} a n d \frac{x - 2}{1} = \frac{y + 3}{- 4} = \frac{z + 1}{5}$ is 11x + my + nz = 28, where

m = –1, n = 3

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m = 1, n = –3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m = –1, n = –3

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m = 1, n = 3

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\frac{x - 3}{1} = \frac{y - 2}{4} = \frac{z - 1}{5} a n d \frac{x - 2}{1} = \frac{y + 3}{- 4} = \frac{z + 1}{5}

\frac{x}{4} = \frac{y}{2} = \frac{z}{1}

\frac{x - 4}{1} = \frac{y - 5}{4} = \frac{z - 9}{2}

\frac{x + 8}{4} = \frac{y + 6}{2} = \frac{z - 2}{1}

\frac{x - 4}{2} = \frac{y - 5}{2} = \frac{z - 3}{1}

x + y + z = 2

\frac{x + 2}{3} = \frac{y - 2}{5} = \frac{z + 5}{7}

\frac{x - 1}{1} = \frac{y - 4}{4} = \frac{z + 4}{7}

\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z}{3}

\frac{x}{4} = \frac{y - 2}{- 2} = \frac{z + 1}{6}

\frac{x - 2}{3} = \frac{y - 1}{1} = \frac{z - 2}{5}

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