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Question

The plane x2+y3+z1=1 meets the co - ordinate axes in the points A,B,C respectively. The area of triangle ABC in square units is :

A
52
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B
72
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C
92
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D
None of these
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Solution

The correct option is B 72
The plane x2+y3+z1=1 meets the co - ordinat axes in the points A,B,C respectively.
Therefore, OA=2i, OB=3j, OC=k
Area of triangle ABC =Δ
=∣ ∣AB×AC2∣ ∣
=(3j2i)×(k2i)2
=3i+2j+6k2
=72
Ans: B

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