The plane x2+y3+z1=1 meets the co - ordinate axes in the points A,B,C respectively. The area of triangle ABC in square units is :
A
52
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B
72
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C
92
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D
None of these
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Solution
The correct option is B72 The plane x2+y3+z1=1 meets the co - ordinat axes in the points A,B,C respectively. Therefore, →OA=2i, →OB=3j, →OC=k Area of triangle ABC=Δ