The plane passing through the point (−2,−2,2) and containng the line joining the points (1,1,1) & (,1,−1,2) makes intercept of length a,b,c an aes of x,y,z respectively then
A
a=3b
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B
a+b+c=12
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C
No. of ways to distribute (3b+6c) alike objects among a2 boys =19C4
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D
tan(π(b+c)2a)=1
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Solution
The correct options are Aa=3b Ba+b+c=12 C No. of ways to distribute (3b+6c) alike objects among a2 boys =19C4 since a= length of x - intercept =8 b= length y - = 83 C= length =86 A) a=3b B) b+b+c=8+83+86=12 c) 3b+6c=16a2=82=4