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Question

The plane which bisects the line segment joining the points (−3,−3,4) and (3,7,6) at right angles, passes through which of the following points:

A
(2,1,3)
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B
(4,1,2)
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C
(4,1,2)
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D
(2,3,5)
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Solution

The correct option is C (4,1,2)
The mid point of the given points (3,3,4) and (3,7,6) is (0,2,5) which lies on the plane.
The D.Rs of the normal of the plane is (6,10,2)
Hence, equation of the plane is 6(x0)+10(y2)+2(z5)=0
6x+10y+2z=30
3x+5y+z=15
Hence, we can observe that only (4,1,2) lies on the plane.

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