The correct option is C (4,1,−2)
The mid point of the given points (−3,−3,4) and (3,7,6) is (0,2,5) which lies on the plane.
The D.R′s of the normal of the plane is (6,10,2)
Hence, equation of the plane is 6(x−0)+10(y−2)+2(z−5)=0
⇒6x+10y+2z=30
⇒3x+5y+z=15
Hence, we can observe that only (4,1,−2) lies on the plane.