The plane which is parallel to plane 3x - 3y +4z =7 is .

3x - 3y +4z = 1

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4x - 3y +4z = 7

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3x - 4y +4z = 7

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3x + 3y -4z = 7

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Solution

The correct option is A 3x - 3y +4z = 1
We know that the equation of a plane parallel to ax +by + cz + d = 0 can be given by ax +by + cz + k = 0.

So, the equation of a plane parallel to 3x - 3y +4z = 7 will be 3x - 3y +4z = k where k can be any real constant. Out of the options given we have 3x - 3y +4z = 1 as the correct answer.

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Similar questions

Which of the following is parallel to plane 3x - 3y +4z = 7?

The equation of the plane through (1, 2, 3) and parallel to the plane 2x + 3y - 4z = 0 is

m

3 x - 2 y + z + 3 = 0 = 4 x - 3 y + 4 z + 1

2 x - y + m x - 2 = 0

m

3 x - 2 y + z + 3 = 0 = 4 x - 3 y + 4 z + 1

2 x - y + m z - 2 = 0

2 x + 3 y + 4 z = 7

2 x + 3 y + 4 z = 17

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