The planes $2 x - y + 4 z = 5$ and $5 x - 2.5 y + 10 z = 6$ are

Parallel

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Perpendicular

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Intersect

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intersect

x

axis

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Solution

The correct option is B Parallel
Planes are $2 x - y + 4 z = 5$
and $5 x - 2.5 y + 10 z = 6$
Multiply both sides by 2 to the second equation
$\Rightarrow 10 x - 5 y + 20 = 12$
Now divide both sides by $2$
$\Rightarrow 2 x - y + 4 z = \frac{12}{5}$

Clearly both planes are parallel

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Similar questions

Q. The planes:

2 x - y + 4 z = 5

and

5 x - 2.5 y + 10 z = 6

are

Q. The planes: 2 x − y + 4 z = 5 and 5 x − 2.5 y + 10 z = 6 are (A) Perpendicular (B) Parallel (C) intersect y -axis (C) passes through

The planes: 2x − y + 4z = 5 and 5x − 2.5y + 10z = 6 are

(A) Perpendicular (B) Parallel (C) intersect y-axis

Choose the correct answer in Question
The planes 2x - y + 4z = 5 and 5x - 2.5y + 10z = 6 are
(a) perpendicular
(b) parallel
(c) intersect along Y-axis
(d) passes through $(0, 0, \frac{5}{4})$

Q. Find the distance between the planes

2 x - y + 2 z = 5

and

5 x - 2.5 y + 5 z = 20

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The planes 2x−y+4z=5 and 5x−2.5y+10z=6 are

The correct option is B ParallelPlanes are 2x−y+4z=5 and 5x−2.5y+10z=6Multiply both sides by 2 to the second equation⇒10x−5y+20=12Now divide both sides by 2⇒2x−y+4z=125Clearly both planes are parallel

The planes $2 x - y + 4 z = 5$ and $5 x - 2.5 y + 10 z = 6$ are

The correct option is B Parallel
Planes are $2 x - y + 4 z = 5$
and $5 x - 2.5 y + 10 z = 6$
Multiply both sides by 2 to the second equation
$\Rightarrow 10 x - 5 y + 20 = 12$
Now divide both sides by $2$
$\Rightarrow 2 x - y + 4 z = \frac{12}{5}$

Clearly both planes are parallel