Question

The plastic modulus for the T-section as shown in figure below is _____$c{m}^3$

Answer 1

Area of compression zone = Area of tension zone
$1500+10x=(200-x)\times 10$
$x=25mm$

Total area of the section,
$A=150\times 10+10\times 200=3500m{m}^2$

$=\frac{A}{2}=\frac{3500}{2}=1750m{m}^2$

$\therefore Plasticmodulus;z_p=\frac{A}{2}(\overline{y_1}+{\overline{y}}_2)$
where,
$\overline{y_1}=\frac{150\times 10\times 30+10\times 25\times 12.5}{1750}=27.5mm$
$\overline{y_2}=\frac{175}{2}=87.5mm$

$\therefore z_p=\frac{A}{2}\left(\overline{y_1+\overline{y_2}}\right)$
$=1750(27.5+87.5)=201250m{m}^3$
$=201.25c{m}^3$