Question

The plate separation in a parallel plate condenser is d and plate area is A. If it is charged to V volt and battery is disconnected then the work done in increasing the plate separation to 2d will be

• A. $\frac{3}{2}\frac{{ϵ}_{0}A{V}^2}{d}$
• B. $\frac{{ϵ}_{0}A{V}^2}{d}$
• C. $\frac{2{ϵ}_{0}A{V}^2}{d}$
• D. $\frac{{ϵ}_{0}A{V}^2}{2d}$

Answer 1

The correct option is

D

$\frac{{ϵ}_{0}A{V}^2}{2d}$