The plates of a parallel plate capacitor are charged with surface densities σ1 and σ2(σ1=σ and σ2=−σ) respectively and placed horizontally. The electric field at points :
A
inside the region between the plates will be zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
above the upper plate and below the lower plate will be zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
everywhere in space will be zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
inside the region between the plates will be uniform and non zero (neglecting other effects)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are B above the upper plate and below the lower plate will be zero D inside the region between the plates will be uniform and non zero (neglecting other effects) The electric field due to charged plate, E=σ2ϵ0 The field lines are shown in figure. The electric field above the upper plate, E=σ2ϵ0+−σ2ϵ0=0 Electric field at the center,E=σ2ϵ0+σ2ϵ0=σϵ0 Electric field below the lower plate,E=σ2ϵ0+−σ2ϵ0=0 Ans: (B),(D)