The plates of a parallel-plate capacitor are not exactly parallel. The surface charge density, therefore,
A
is smallest where the plates are closet
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B
is higher at the closer end
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C
will not be uniform
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D
each plate will have the same potential at each point
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Solution
The correct options are A is higher at the closer end B will not be uniform D each plate will have the same potential at each point If the plates are metallic, its a equipotential surface. So the potential will be same at each point on the plates. Since Q=CV=AϵV/d Hence, Q is inversely proportional to d. So at closer end, Q and Surface charge density would be highest.