The plot of velocity (v) versus displacement (x) of a particle executing simple harmonic motion is shown in figure. The time period of oscillation of particle is

\frac{π}{2} s

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π s

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2 π s

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3 π s

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Solution

The correct option is A $\frac{π}{2} s$
Row Hg
$V_{m a x} = A w = 0. u m / s$
$x_{m a x} = A = 10$
$\frac{A w}{A} = \frac{0. u}{10 \times 10^{- 2}} = \frac{40}{10} = 4$
$w = 4$
$T = \frac{2 π}{w} = \frac{2 \times π}{4}$
$∴ T = π / 2^{s}$
Answer is A

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The plot of velocity (v) versus displacement (x) of a particle executing simple harmonic motion is shown in figure. The time period of oscillation of particle is

The correct option is A π2sRow HgVmax=Aw=0.um/sxmax=A=10AwA=0.u10×10−2=4010=4w=4T=2πw=2×π4∴T=π/2s Answer is A

The correct option is A $\frac{π}{2} s$
Row Hg
$V_{m a x} = A w = 0. u m / s$
$x_{m a x} = A = 10$
$\frac{A w}{A} = \frac{0. u}{10 \times 10^{- 2}} = \frac{40}{10} = 4$
$w = 4$
$T = \frac{2 π}{w} = \frac{2 \times π}{4}$
$∴ T = π / 2^{s}$
Answer is A