The plot represents the flow of current through a wire at three different times. The ratio of charges flowing through the wire at different times is

2 : 1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 : 3 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1 : 1 : 1
Since current, $i = \frac{d Q}{d t}$
$\Rightarrow d Q = i d t$
Integrating,
$\int d Q = \int i d t$
Hence total charge will the area under the $i - t$ graph.
For $t = 1 - 2$ sec
Area, $A_{1} = I \times t = (2 - 0) (2 - 1) = 2$
For $t = 3 - 5$ sec
Area, $A_{2} = I \times t = (1 - 0) (5 - 3) = 2$
For $t = 6 - 8$ sec
Area, $A_{3} = \frac{1}{2} (8 - 6) (2 - 0) = 2$
Ratio of area, $A_{1} : A_{2} : A_{3} = 2 : 2 : 2 = 1 : 1 : 1$
Hence ratio of charges is also $1 : 1 : 1$

Suggest Corrections

Similar questions

Q. The plot represents the flow of current through a wire at three different times. The ratio of charges flowing through the wire at different times is:

Q. The current flowing through a wire depends on time as

I = 3 t^{2} + 2 t + 5

. The charge flowing through the cross-section of the wire in time from

t = 0

t = 2 s

The current flowing through a wire depends on time as $I = 3 t^{2} + 2 t + 5.$ The charge flowing through the cross-section of the wire in time from t = 0 to t = 2s is:

Q. Charge on an electron is

1.6 \times 10^{- 19}

coulomb. Number of electrons passing through the wire per second on flowing of 1 ampere current through the wire will be

Q. A current of 5 amperes flows through a wire whose ends are at a potential difference of 3 volts. Calculate the resistance of the wire.

Join BYJU'S Learning Program