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Question

The plot represents the flow of current through a wire at three different times. The ratio of charges flowing through the wire at different times is
782508_d6cf60d572b1472180ddf5d03d37e62c.png

A
2:1:2
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B
1:3:3
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C
1:1:1
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D
2:3:4
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Solution

The correct option is C 1:1:1

Step 1: Area under graph

We know that q=i×dt

So, charge flowing through wire equals the area under curve of It graph

In 1st case Area =base×height=1×2=2
So, q1=2C
In 2nd case , Area =base×height=2×1=2
So, q2=2C
In 3rd case Area =12×base×height=12×2×2=2
So, q3=2C

Step 2: Ratio of charges
q1:q2:q3 =1:1:1

Hence, Option C is correct

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