The plots of intensity versus wavelength for three black bodies at temperatures $T_{1}, T_{2}$ and $T_{3}$ , respectively are as shown. Their temperatures are such that

T_{1} > T_{2} > T_{3}

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T_{1} > T_{3} > T_{2}

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T_{2} > T_{3} > T_{1}

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T_{3} > T_{2} > T_{1}

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Solution

The correct option is B $T_{1} > T_{3} > T_{2}$
According to Wien's law, $λ T = c o n s t a n t$ . From the graph
$λ_{1} < λ_{3} < λ_{2}$
$∴ T_{1} > T_{3} > T_{2}$ .

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The correct option is B T1>T3>T2According to Wien's law, λT=constant. From the graphλ1<λ3<λ2∴T1>T3>T2.

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The correct option is B $T_{1} > T_{3} > T_{2}$
According to Wien's law, $λ T = c o n s t a n t$ . From the graph
$λ_{1} < λ_{3} < λ_{2}$
$∴ T_{1} > T_{3} > T_{2}$ .