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Question

The pOH of 108 MHCl is :

A
8
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B
6
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C
between 6 and 7
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D
between 7 and 8
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Solution

The correct option is D between 7 and 8
[H+] from HCl = 108 M
[H+] from H2O = 107 M
total [H+]=(108+107)=1.1×107 M
we know that pH=log10[H+]
pH=log10(1.1×107)=70.0414=6.9
Also, pH+pOH=14
6.9+pOH=14
pOH=146.9=7.1
hence, pOH of 108 M HCl is between 7 and 8

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