The pOH of a solution of NaOH is 11.00. What is the [H+] for this solution?
1.0 x 10-3
2.5 x 10-3
5.0 x 10-12
4.0 x 10-12
pOH = 14 - pH
11 = 14 - pH
pH = 14 - 11 = 3
pH = - log [H+]
-3 = log [H+]
[H+] =Anti [- 3]
[H+] = 0.001
The hydroxide ion concentration of a solution is 1.0×10−9 M. What is the pH of this solution?
If the value of the solubility product for AgBr is 4.0 x 10-12 at 25 °C, calculate the solubility of AgBr(s) in water.
KspMg(OH)2 is 4.0×10−12. The number of moles of Mg2+ ions in one litre of its saturated solution in 0.1 M NaOH is :