The point(-4,-1) lies on a line of the equation

2x-3y=5

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2x+3y=4

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4x-2y=6

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2x-4y=-4

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Solution

The correct option is D
2x-4y=-4

The point(-4,-1) lies on a line of the equation 2x-4y=-4:

LHS = 2 x -4 - 4 x -1 = -4 = RHS

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Similar questions

The point(-4,-1) lies on a line of the equation

z^{4} = {(1 + z)}^{4}

(- 1, 1)

(2, - 4) .

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