The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A'', then find the coordinates of A'' .

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Solution

Image of point A(4, 6) when reflected in the origin will be (-4, -6)

So $A^{'} \equiv (- 4, - 6)$

Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).

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The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A'', then find the coordinates of A'' .

Image of point A(4, 6) when reflected in the origin will be (-4, -6) So A′≡(−4,−6) Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).

Image of point A(4, 6) when reflected in the origin will be (-4, -6)

So $A^{'} \equiv (- 4, - 6)$

Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).