The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A'', then coordinates of A'' will be

(-4, 6)

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(4, 6)

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(4, -6)

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(-4, -6)

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Solution

The correct option is C
(4, -6)

Image of point A(4, 6) when reflected in the origin will be (-4, -6)

So $A^{'} \equiv (- 4, - 6)$

Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).

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Similar questions

Q. The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A'', then find the coordinates of A'' .

The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A".

(i) Write down the co-ordinates of A".

(ii) Write down a single transformation that maps A onto A".

The point A (a, b) is first reflected in the y-axis and then reflected in the origin to a point A'(- 3, 4). The value of a and b are $a = - 4$ and $b = - 3$ .

The point P (a, b) is first reflected in the origin and then reflected in the y-axis to P'. If P' has co-ordinates (4, 6); evaluate a and b.

The image of point (4, -6) under the operation $M_{x} . M_{y}$ is

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The point A(4, 6) is first reflected in the origin to point A'. Point A' is then reflected in the y-axis to point A'', then coordinates of A'' will be

The correct option is C (4, -6) Image of point A(4, 6) when reflected in the origin will be (-4, -6) So A′≡(−4,−6) Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).

The correct option is C
(4, -6)

Image of point A(4, 6) when reflected in the origin will be (-4, -6)

So $A^{'} \equiv (- 4, - 6)$

Now image of A'(-4, -6) when reflected in the y - axis will be (4, -6).