You visited us 1 times! Enjoying our articles? Unlock Full Access!

Global Maxima

The point A o...

Question

The point A of the parabola $y^{2} = 4 a x$ for which $| A B - A C |$ is maximum, where $B = (0, a)$ and $C = (- a, 0)$ is

(a, 2 a)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(4 a, 4 a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a, - 2 a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $(a, 2 a)$
y = x + a
(x+a)^2 = 4ax
x^2 + a^2 + 2ax = 4ax
x^2 + a^2 + 2ax - 4ax = 0
x - 2ax + a^2 = 0
x = a
y= x+a
y= a+a
y= 2a
x=a , y = 2a

Suggest Corrections

Similar questions

y^{2} = 4 a x

| P R - P Q |

y^{2} = 4 a x

(2 a, 3 a)

k x + m y + 4 a = 0; p x - h y + a = 0

| k + m + p + h |

(2 a, 4 a)

(2 a, 6 a)

(2 a + \sqrt{3} a, 5 a)

a > 0

y^{2} = 4 a (x + a)

A (2 a, 4 a)

B (2 a, 6 a)

C (2 a + \sqrt{3} a, 5 a)

a > 0

Join BYJU'S Learning Program