The point C divides the line segment AB in the ratio 3:7. Find the length of AB (in cm) if the line segment BC is 3.5 cm long -

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Solution

$\frac{A C}{B C}$ = $\frac{3}{7}$

Therefore, $\frac{A B}{B C}$ = $\frac{B C}{B C}$ + $\frac{A C}{B C}$ = 1+ $\frac{3}{7}$ = $\frac{10}{7}$

$\frac{A B}{B C}$ = $\frac{10}{7}$ . So, AB=BC $\times$ $\frac{10}{7}$ = 5 cm.

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The point C divides the line segment AB in the ratio 3:7. Find the length of AB (in cm) if the line segment BC is 3.5 cm long - ___

ACBC =37 Therefore, ABBC= BCBC + ACBC = 1+ 37 = 107 ABBC = 107. So, AB=BC × 107 = 5 cm.

The point C divides the line segment AB in the ratio 3:7. Find the length of AB (in cm) if the line segment BC is 3.5 cm long -

___

$\frac{A C}{B C}$ = $\frac{3}{7}$

Therefore, $\frac{A B}{B C}$ = $\frac{B C}{B C}$ + $\frac{A C}{B C}$ = 1+ $\frac{3}{7}$ = $\frac{10}{7}$

$\frac{A B}{B C}$ = $\frac{10}{7}$ . So, AB=BC $\times$ $\frac{10}{7}$ = 5 cm.