The point from where a ball of mass 2kg is projected is taken as the origin of the co-ordinate axes. The x and y components of its displacement are given by x=6t and y=8t−5t2. Find the average force on it from t=0s to t=2s seconds.
A
20N
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B
40N
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C
60N
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D
80N
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Solution
The correct option is B40N ux=6m/s;uy=8m/s; and g=10m/s2; In projectile motion, there is no change in velocity in the horizontal direction. Hence there is no impulse in that direction. But in vertical direction, momentum changes. Hence vy−uy=gt=20m/s Impulse =m(vy−uy)=2×20=40kg m/s.