The point in the graph of $y = x^{2} - 2 x + 3$ where it attains the minimum value is

(2, 3)

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(1, 2)

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(1, 3)

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(–1, –3)

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Solution

The correct option is B
(1, 2)

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f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} | x^{3} + x^{2} + 3 x + sin x | \cdot (3 + sin \frac{1}{x}), & x \neq 0 0, & x = 0 \end{matrix}

f (x)

y = g (x)

(1, 2),

y = g (x - 3) - 4

For all real values of x, the minimum value of is

(A) 0 (B) 1

f (x) = \sqrt{5 |x| - x^{2} - 6}

The domain of the function $f (x) = \sqrt{5 | x | - x^{2} - 6}$ is

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