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Question

The point in the interval (0,2π), where f(x)=exsinx has maximum slope is

A
π4
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B
π2
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C
π
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D
π3
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Solution

The correct option is B π2
f(x)=exsinxf(x)=excosx+sinx exf(x)=ex(sinx+cosx)for maximum slopef′′=ex(cosxsinx)+(sinx+cosx)ex=0f′′=2excosx=0x=π/2

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