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Question

The point in which the join of A(- 9, 4, 5) and B(11, 0, -1) is met by the perpendicular from the origin


A

(2, 2, 1)

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B

(2, 1, 2)

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C

(1, 2, 2)

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D

(2, 2, 2)

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Solution

The correct option is C

(1, 2, 2)


Let P be the required point on AB. Let P divides AB in the ratio λ:1

P = (11λ9λ+1,4λ+1,5λλ+1) , OP⊥ AB ⇒ 20(11λ9λ+1)-4(4λ+1)-6(5λλ+1)=0

λ=1 ⇒ P=(1,2,2)


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