Question

The point $\left(0,3\right)$ lies on the graph of the linear equation

• A. $3x+4y=12$
• B. $3x-4y=12$
• C. $3x-4y=10$
• D. $3x+4y=10$

Answer 1

The correct option is A

$3x+4y=12$

Explanation for the correct option:

Step 1: Substituting the value in the equations and checking for $\text{LHS = RHS}$

Option A; $3x+4y=12$

$$\begin{gathered} LHS \\ =3\times 0+4\times 3 \\ =12 \\ RHS \\ =12 \\ LHS=RHS \end{gathered}$$

Hence $\left(0,3\right)$ satisfies the given equation

Option B:$3x-4y=12$

$$\begin{gathered} LHS \\ =3\times 0-4\times 3 \\ =-12 \\ RHS \\ =12 \\ LHS\ne RHS \end{gathered}$$

Hence $\left(0,3\right)$ does not satisfy the given equation

Option C:$3x-4y=10$

$$\begin{gathered} LHS \\ =3\times 0-4\times 3 \\ =-12 \\ RHS \\ =10 \\ LHS\ne RHS \end{gathered}$$

Hence $\left(0,3\right)$ does not satisfy the given equation

Option D $3x+4y=10$

$$\begin{gathered} LHS \\ =3\times 0+4\times 3 \\ =12 \\ RHS \\ =10 \\ LHS\ne RHS \end{gathered}$$

Hence $\left(0,3\right)$ does not satisfy the given equation

Therefore the correct option is A.