The point of application of the force (−2,4,7) is displaced from the point (3,−5,1) to the point (5,9,7), but the force is suddenly halved when the point of application moves half the distance.The work done by the force is
A
70
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B
70.5
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C
75
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D
75.5
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Solution
The correct option is B70.5 Resultant vector of two points is given by
¯¯¯r=(2,14,6)
We know w=F⋅¯¯¯r2+F2⋅¯¯¯r2 =34¯¯¯¯F⋅¯¯¯r=34(−4+56+42) =472×3 =(23.5)×3 =70.5