The point of concurrency of the altitudes drawn from the vertices A(at1t2,a(t1+t2)),B(at2t3,a(t2+t3)) and C(at3t1,a(t3+t1)) of the triangle ABC (where t1≠t2≠t3)is
A
(−at1t2t3,a(t1+t2+t3))
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B
(−a,a(t1+t2+t3+t1t2t3))
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C
(−at1t2t3,a(t1t2+t2t3+t3t1))
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D
(0,0)
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Solution
The correct option is B(−a,a(t1+t2+t3+t1t2t3))
mAB=1t2,mBC=1t3 and mCA=1t1 ∵AD⊥BC,CF⊥AB and BE⊥AC ∴mAD=−t3,mCF=−t2 and mBE=−t1
Equation of AD is y−a(t1+t2)=−t3(x−at1t2)…(1)
Equation of CF is y−a(t3+t1)=−t2(x−at3t1)…(2)
Solving equations (1) from (2), we get x=−a and y=a(t1+t2+t3+t1t2t3)
Hence, the point of concurrency of the altitudes is (−a,a(t1+t2+t3+t1t2t3)).