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Question

The point of concurrency of the altitudes drawn from the vertices A(at1t2,a(t1+t2)),B(at2t3,a(t2+t3)) and C(at3t1,a(t3+t1)) of the triangle ABC (where t1t2t3) is

A
(at1t2t3,a(t1+t2+t3))
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B
(a,a(t1+t2+t3+t1t2t3))
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C
(at1t2t3,a(t1t2+t2t3+t3t1))
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D
(0,0)
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Solution

The correct option is B (a,a(t1+t2+t3+t1t2t3))

mAB=1t2,mBC=1t3 and mCA=1t1
ADBC,CFAB and BEAC
mAD=t3,mCF=t2 and mBE=t1

Equation of AD is ya(t1+t2)=t3(xat1t2) (1)
Equation of CF is ya(t3+t1)=t2(xat3t1) (2)

Solving equations (1) from (2), we get
x=a and y=a(t1+t2+t3+t1t2t3)

Hence, the point of concurrency of the altitudes is
(a,a(t1+t2+t3+t1t2t3)).

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