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Question

The point of contact of line 5x+12y=9 and hyperbola x2−9y2=9 will lie on

A
4x+15y=0
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B
7x+12y=19
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C
4x+15y+1=0
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D
7x12y=19
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Solution

The correct options are
A 4x+15y=0
B 7x+12y=19
Given hyperbola and the line may be written as, x29y21=1 and 5x943y1=1 respectively.
Comparing with standard form point of contact is (5,43)
Clearly option 'A' and 'B' are satisfying this point.

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