The point of contact of line 5x+12y=9 and hyperbola x2−9y2=9 will lie on
A
4x+15y=0
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B
7x+12y=19
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C
4x+15y+1=0
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D
7x−12y=19
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Solution
The correct options are A4x+15y=0 B7x+12y=19 Given hyperbola and the line may be written as, x29−y21=1 and 5x9−−43y1=1 respectively. Comparing with standard form point of contact is (5,−43) Clearly option 'A' and 'B' are satisfying this point.