Question

The point of contact of the tangent to the circle $x^2+y^2=5$ at the point (1, -2) which touches the circle $x^2+y^2-8x+6y+20=0$, is

• A. (2,-1)
• B. (3,-1)
• C. (4,-1)
• D. (5,-1)

Answer 1

The correct option is B (3,-1)

Equation of the tangent at (1,-2) to the circle $x^2+y^2=1$ is $x-2y=5$.
Here, only point (3,-1) lies on the tangent.