The point of intersection of $2 x + 3 y = 6, x - y = 3$

(3, 0)

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(4, 0)

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(0, 3)

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(0, 4)

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Solution

The correct option is B $(3, 0)$
$x - y = 3 x = 3 + y 2 (3 + y) + 3 y = 6 4 y = 0 y = 0 x = 3$

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Which point on x-axis is equidistant from the points A(7, 6) and B(-3, 4) ?

(a) (0, 4) (b) (-4, 0) (c) (3, 0) (d) (0, 3)

2 x + 3 y - 6 = 0, 4 x - 3 y - 6 = 0, x = 2

y = \frac{2}{3}

The graph of the linear equation 2x + 3y = 6 meets the y - axis at the point

(a) (2, 0)

(b) (3, 0)

(d) (0, 3)

2 x + 3 y - 6 = 0, 4 x - 3 y - 6 = 0, x = 2, a n d y = \frac{2}{3}

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