The point of intersection of emergent rays is :

2 cm left of o.

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2 cm right of o.

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1 cm left of o.

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1 cm right of o.

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Solution

The correct option is B 2 cm right of o.
The point of intersection will be equal to the apparent shift caused in the image of the object.
$δ s = t (1 - \frac{1}{μ})$
= $3 (1 - \frac{1}{3})$
= $2 c m$

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