The correct option is A (6,5)
The point of intersection of tangents at any two points A(at12,2at1) and B(at22,2at2) on the parabola y2=4ax is given by (at1t2,a(t1+t2))
2at1=4, 2at2=6
For the parabola y2=4x
⇒ a=1⇒t1=2,t2=3
Then point of intersection of tangents is (1×2×3,1×(2+3))=(6,5)