The point of intersection of the curves whose parametric equations are $x = t^{2} + 1, y = 2 t$ and $x = 2 s, y = 2 / s$ is given by

(4, 1)

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(2, 2)

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(- 2, 4)

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(1, 2)

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Solution

The correct option is C $(2, 2)$
For point of intersection, $t^{2} + 1 = 2 t, 2 t = \frac{2}{s}$
$\Rightarrow (t - 1)^{2} = 0, t = \frac{1}{s}$
$\Rightarrow t = 1 \Rightarrow s = 1$
Thus point of intersection is $(2, 2)$

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