The point of intersection of the line joining the points (2, 4, 5) and (−4, 3, −2) and the xy plane is
Given points are A(2,4,5) and B(−4,3,−2). Let xy plane divide the
line joining the points in the ratio of k:1
For x-y plane, z-coordinate must be zero
k(−2)+1(5)k+1=0
−2k+5=0
2k=5
k=52
So,xy plane divides the joining the points (2,4,5) and (-4,3,-2) in the ratio of 5:2
X-coordinate =5(−4)+2(2)5+2
⇒ −20+47=−167
Y-coordinate y=5(3)+2(4)5+2
=15+87 = 237
Intersection of the line joining the points (2,4,5) and (-4,3,-2) and the xy plane is
(−167,237,0)